33
dig Pons
Last seen 1 month ago
Member for 2 years, 1 month, 22 days
Difficulty Easy
Looking for a code job... just because it is a hobby for me :)
If interested: trucbalear@gmail.com
First OOP in checkio or first OOP ever? Because you seem to be comfortable with objects!
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wow!very creative the way you used to solve it with the dict :) Also very smart when using try except to avoid more code
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Since there is too many (but easy) instructions, maybe would be fine to simplify some instructions like
if not c:
c, t = '', ''
elif c > 0:
t = ' + '
elif c < 0:
c, t = abs(c), ' - '
to
c = '' if not c else abs(c)
t = '' if not c else ' + ' if c >
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Nothing to say! Only, maybe a bit more elegant to write
if not any(horses):
raise ValueError
instead of
if horses == [[]]:
raise ValueError
but just for comment something ;)
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I don't know why I couldn't manage with this task in a simple way... At the beginning sounds easier than as it is when you do it
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Are not the same nums = {*args} and nums = {args}? I thought also you could not work in the first way
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Why do you use text.replace? In this case it would not pass "it is a cone" with second argument {cone, one}
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Very well resoluted and very clear! Maybe you could have joined first 2 lines which are after the "for" in one using set: len(set(game_result[i])) == 1 and '.' not in...
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Using text.find(begin) you would have had the index of begin without needing indexes (so you use index_begin+len(begin) or something like that). But yeah, actually it is a very nice code!
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Much more simpler than mine ;)
Here I write you how I would have coded it using the same idea you had:
def checkio(n, m):
bin_n, bin_m = bin(n)[2:], bin(m)[2:]
len_diff = abs(len(bin_n) - len(bin_m))
bin_m = '0'*len_diff + bin_m
return sum(1 for i, j in zip(bi
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You solved much shorter as I did when I did it! Today I know (maybe you too) a way to transpose a matrix so you can sum colums in a easy way as rows:
transpose_matrix = zip(*matrix)
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Nice use of num//10 which is always true (or not false) when is not zero! Neve used un your way ;)
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I tested for myself the difference between working with lists or strings in this task and seems to be approximately 2 times faster bc you create new strings when working with indexes like [1:]
Actually it is more elegant yours, but if you need some more efficiently, something like this would work a
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