brubru777 profile - python coding challenges

11

Second-dandd31 2

`is_alive` should be a "property". To keep it simple, a property is a function which can be invoked like an attribute. Here's the syntax: @property def is_alive(self): # return something More

21

jmegner

recursive touch/infect-jmegner 1 1

Very clean solution. Just a little question. Wouldn't `max` be simpler than `sorted(...)[-1]`? More

45

kurosawa4434

First-kurosawa4434 1 1

Clever solution. To get the metals, a simpler solution would be metal1, metal2 = k.split('-') You could also declare `METALS` as a set at the beginning for efficiency. More

49

Sim0000

Counter-Sim0000 1

Most elegant and efficient solution I've seen. More

12

Sorrop

First-Sorrop 1 1

Hi, Here's a little Python trick. You can replace your last if by return min_quantities[-1] or None If `min_quantities[-1]` is not 0 (i.e. is `True`), it will be returned. If it is 0 (i.e. is `False`), `None` will be returned. More

57

veky

filter-veky 1 1

I was surprised to see so many negative comments for your solution. It is a similar to mine but a bit more compact and I dare say "elegant". Whether it respects the format you're supposed to use for answering or not isn't really relevant. The purpose of being able to look at other people's code is t More

32

fokusd

First-fokusd 1

Simple and elegant. I love it. More

49

Sim0000

First-Sim0000 1

Nice short solution but you could greatly improve its readability with meaningful variable names. More

9

stum74

First-stum74 1

Instead of `n > len(array) - 1`, I find `n >= len(array)` more natural. But that's just a detail. More

9

gsbullmer

First-gsbullmer 1

Sure. With your algorithm, you check every value between the min and the max. If max - min = 1,000,000,000, you're going to check 1,000,000,000 numbers even if the array has only two elements. If you sort the array first, you only need to check pairs of consecutive numbers in the array. If their d More