I admire the brevity of it. Your return line: return int(angle) if int(angle) == angle else angle *Slow Clap* Brilliant! This is the kind of stuff I need to do a lot more often. What you did in one line took me like 4 lines with two nested 'if' statements to get done. One question though, More

I'm really very stupid lol. I just realized I didn't need a whole chunk of what I submitted. Here's what it should have been: def between_markers(text: str, begin: str, end: str) -> str: """ returns substring between two given markers """ if begin in text: tb = text More

I used almost the same solution, but I like yours slightly better than mine. I did this: def checkio(data: str) -> bool: m = re.compile(r"^(?=.*[a-z])(?=.*[A-Z])(?=.*\d)[a-zA-Z\d]{10,}$") if m.match(data) is not None: return True else: More

Damn. Why didn't I think of that? I have to say, I really hate you. Well done. It only took me about 40 lines of code to accomplish the exact same thing, lol. I am disgusted by the fact that this works. Damn you. Good work. More

Terrible! 0/5 Stars! You should be ashamed of yourself! More

WOW YOU'RE RIGHT, EXTREMELY USEFUL. I AM INDEED IMPRESSED. More

Excellent code! What a genius this guy is, whoever he may be! 10/10 let's hire this guy immediately and pay him 10 times what he's worth! Amazing!!! More