wo.tomasz profile - python coding challenges

wo.tomasz

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Tomasz Wójcik

Last seen 5 days ago

Member for 4 years, 2 months, 25 days

Difficulty Normal

Best reviews / Newest reviews

obone

First and Last-obone 1

Use strftime("%A") instead of array with days names More

Mroovka

First-Mroovka 1 1

I believe that it can be done more easily. You don't need a special case for len (array) == 1: the code in 'else' will do the same More

Mroovka

First-Mroovka 1

You have a similar situation with "if i == 0:" and "elif i% 2 == 0" More

Tinus_Trotyl

simulator-Tinus_Trotyl 1

Better is use "isdigit()" then key in '0123456789' More

ninjagozhane

First-ninjagozhane 1

In my opinion better is use if statement then try in this case More

trang_a2k100

First-trang_a2k100 1 1

return your condition directly More

Lemur21

First-Lemur21 1

You can use math.gcd() instead define own one More

kdim

while and sum-kdim 1

I think it's better to use the // operator instead of casting to str More

lucas.stonedrake

.replace() or re.sub()-lucas.stonedrake 1

I think that re.sub() only makes sense when you use a regular expression. If everything fits, you better use replace(). More

IliaLiash

string, replace-IliaLiash

I think it is better to work with objects than to treat objects as text. More

Sebdidier

1 line-Sebdidier

I think it is better to work with objects than to treat objects as text. More

JasonVoorhees666

Repr-JasonVoorhees666

I think it is better to work with objects than to treat objects as text. More

pbPy

regex-pbPy

Any import should be on top of file More

Oleg_Levonjuk

First-Oleg_Levonjuk

I think this solution too complicated. The most frequent day of the week of the year is the last day of the year :) When there is a common year of such days, we have 2. More

JumpCutter

Recursion-JumpCutter

Probably the shortest solution to this task :) More

Kyrylo_Kireiev

First-Kyrylo_Kireiev

Why don't you just return this condition? More

Alexander_Samrega

First-Alexander_Samrega

Maybe better is use "set" instead of list already_yield. W that case you don't need check "substring not in already_yield" More

Mroovka

First-Mroovka

counter += 1 looks better in my opinion then counter = counter + 1 More

Mroovka

First-Mroovka

You don't need to check if the string contains "." or "," just replace them with "" More

Mroovka

First-Mroovka

The less "if" in your code make it better. Just return text.isupper() More