27
Федор Кудинов
Last seen 11 days ago
Member for 4 years, 9 months, 21 days
Difficulty Normal
I think this solution should be in top ))
No need to invent a wheel if it is in common library
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nice one, clever usage of locals!
never saw format_map
simple format also can be used:
"Hi. My name is {name} and I'm {age} years old".format(**locals())
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coords - I would suggest set usage, since position is not necessary, but remove iterates heavily through this object
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i like this solution more than just using math.gcd function )
oh ok, this is how math.gcd actually works under the hood
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Wow, interesting solution,
But it is expensive to use recursion here, and you have limitation in 2k elements
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expectation is that you yield items 1 by 1
in your case you first process all items, but only then start yielding them
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count_neighbours = lambda grid, row, col: \
looks the same as
def count_neighbours(grid, row, col):
funny, never noticed )
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pattern = re.sub('\[\]', '[^.]', pattern)
good catch, in my solution if I find [] I return False at once, and tests still never fail
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Nice recursive solution, I didn't manage to solve it with recursion
max_total=-1000 you could use float("-inf") instead,
this task can be solved with single loop iteration, as calling recursive function twice in body does not look very effective (I am just jealous :))
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First-gileadslostson
1
Nice solution as does not affect init method, given by task,
For better readability, you could move nested class from body of Capital class
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Nice usage of strip
You can write just as
```
sum(bool(i.strip()) for i in text.split('\n'))
```
sum handles unpacking of generator comprehension,
and it is more memory wise approach
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if you invert condition you can get rid of cumbersome if else block
return end_pointX >= s2[0] and end_pointY >= s2[1]
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line 14 can be removed
I would suggest more descriptive names and spaces around = and > as per PEP8
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you could make it more readable and friendly not trying to fit into minimal amount of code lines
'Readability counts.'
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good idea with str.maketrans('AEIOUY', '000000')
you could remove symbols by re lib:
import re
re.split("\W", text)
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