32
Artur Alexandrov
Last seen 25 days ago
Member for 1 year, 6 months, 19 days
Difficulty Easy
Yes, it's very useful to look into the docs one more time and to learn about not very common, but sometimes very useful alternative parameters, even of the simple functions like int(). Well done.
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Oh, it's such an elegant solution, using orderedDict from collections library. Well done.
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3-liner: easiest-przemyslaw.daniel
Nice, clear and readable solution, using combination of list comprehension and groupby method from itertools library. Well done.
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First-Oleg_Domokeev
It's a very appropriate use of try\except block for solving this task, really helps you to avoid unnecessary if\else blocks at all. Well done.
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First-Jakub_Niedziolka
Maybe it is too complicated to use ord() function for checking digits in string, instead there is a str.isdigit() method, but nevertheless rather unsusal solution.
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Oh, it's a very interesting combination of two libraries. Of course, reduce is very common when you need to transform lots of values to one single value, but mul function instead of lambda is rather creative.
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Oh, lamda inside another lambda)) Not an easy solution to grasp at first, but it looks very compact.
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"Missing Number"-Mateusz_Wryszcz
So, quite readable solution. I've solved this task using the same logic.
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Very good solution, using sum of arithmetic progression, I suppose.
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You can just write with one single line:
return len(password) > 6 without if/else clause, but it's OK.
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4 Annotated Answers-BootzenKatzen
As usual, great solution with full clarification.
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It is a really nice implementation of the Counter method from the collections library. Well done.
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Oh, it's quite elegant and smart to use divmod function for solving this task. Brilliantly done.
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First-Adam.Michalak
It's a very creative solution, using combination of list comprehension and maybe the most common method from collections library. Well done!
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